Question

1. A pendulum is 0.25 m long. What is the frequency of its oscillations?

How do you solve this

Answer 1

hi

Step-by-step explanation:

hi

Answer 2

The frequency is given as 0.996

How to get the frequency

Length(L) = 0.25 meters

For a simple pendulum, the time period (T) is determined by the formula:

`\[ T = 2π * \left((√(L))/(√(g))\right) \]`

Given Length(L) = 0.25 m and acceleration due to gravity (g) = 9.80 m/s²:

`\[ T = 2π * \left((√(0.25))/(√(9.80))\right) \]`

`\[ T = 1.00354496 \text{ seconds} \]`

Frequency (F) is the reciprocal of the time period (T):

`\[ Frequency (F) = (1)/(T) \]`

`\[ Frequency (F) = (1)/(1.00354496) \]`

`\[ Frequency (F) = 0.996467562 \text{ Hz} \]`