Question

If the total mechanical energy of the block spring system is 512 J, what is the amplitude for this oscillation?

Answer 1

A = 2.26 m

Step-by-step explanation:

Given that,

The total mechanical energy of the block spring system is 512 J

Let the spring constant, k = 200 N/m

We need to find the amplitude for this oscillation. The mechanical energy of the spring mass system is given by :

`E=(1)/(2)kA^2`

k is spring constant

`A=\sqrt{(2E)/(k)} \\\\A=\sqrt{(2* 512)/(200)} \\A=2.26\ m`

So, the amplitude of the oscillation is 2.26 m