Answer:
0.55199
Explanation:
When we have a random number of samples, We solve using z score formula
z = (x-μ)/σ/√n where
x is the raw score
μ is the population mean
σ is the population standard deviation
n is random number of samples
z = 0.83/77/√147
z = 0.13069
Probabilty value from Z-Table:
P(x<48.83) = 0.55199
The probability that the mean of the sample would differ from the population mean by less than 0.83 months is 0.55199