Question

Solve for x -

`x {}^(2) - 6x + 5= 0`


ty! ~​

Answer 1

x = 5, x = 1

Explanation:

Hello!

We can solve this quadratic by factoring.

Solve

• 
  `x^2 - 6x + 5 = 0`
• 
  `x^2 - 5x - x + 5 = 0`
• 
  `x(x - 5) - 1(x - 5) = 0`
• 
  `(x - 5)(x - 1) = 0`

Use the zero product property:

1. x - 5 = 0
   x = 5
2. x - 1 = 0
   x = 1

x = 5, or x = 1