Answer:
a = 2, b = 4, c = 8
Explanation:
Let:
First (smallest) number = a
Second number = b
Third number(Largest) = c
The sum of three numbers is 14.
a + b + c = 14...... Equation 1
The largest number is 4 times the smallest number.
c = 4a.... Equation 2
The sum of the smallest and twice the largest is 18.
a + 2c = 18........ Equation 3
We substitute Equation 2 in Equation 3
to solve for a
a + 2(4a) = 18
a + 8a = 18
9a = 18
a = 18/9
a = 2
Hence, the smallest number = 2
We find c
c = 4a.... Equation 2
c = 4(2)
c = 8
The largest number is 8
We find b
a + b + c = 14...... Equation 1
2 + b + 8 = 14
b + 10 = 14
b = 14 - 10
b = 4
What are all three numbers?
a = 2, b = 4, c = 8