Question

How many times would you expect a restriction enzyme that recognizes a 6 base palindrome to cut a 24000 base piece of DNA?

Answer 1

Total number of expected cut = 6 (Approx)

Step-by-step explanation:

Frequency of 6 base sequence = (1/4)⁶

Frequency of 6 base sequence = 1 / 4,096

Find:

Total number of expected cut

Computation:

Total number of expected cut = 24,000 (1 / 4,096)

Total number of expected cut = 5.8593

Total number of expected cut = 6 (Approx)