Answer:
![P_2=2.60atm](https://img.qammunity.org/2021/formulas/chemistry/college/689jmaqbgboiviz3ld5bvb0is6cx4m8bxs.png)
Step-by-step explanation:
Hello!
In this case, since the temperature and pressure are related via a directly proportional relationship, via the Gay-Lussac's law we can write:
![(P_1)/(T_1) =(P_2)/(T_2)](https://img.qammunity.org/2021/formulas/chemistry/college/dr3kh77pch5hh5py1uje8u9ixg8oios10a.png)
Thus, since the initial temperature in kelvins is 294.15 K and the final temperature in kelvins is 364.15 K, we can compute the final pressure as shown below:
![P_2=(P_1T_2)/(T_1) =(2.10atm*364.15K)/(294.15K)\\\\P_2=2.60atm](https://img.qammunity.org/2021/formulas/chemistry/college/tecb03jpqrfgs0wpqk408lmk8kn5h442jg.png)
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