Answer: 0.96875
Explanation:
Probability of obtaining at least one tail on a toss of coin 5 times ;
P(success) in a coin toss = 1/2 = 0.5
Using the binomial distribution formula :
P(x) = nCx * p^x * (1 - p)^(n-x)
P(at least one tail) = 1 - p(0 tails)
P( 0 tails) = 5C0 * 0.5^0 * 0.5^(5-0)
= 1 * 1 * 0.03125
= 0.03125
P(at leat 1 tail) = 1 - 0.03125
P(atleast 1 tail) = 0.96875