Answer:
The energy lost to the environment is 0.461 J
Step-by-step explanation:
Given;
mass of the magnet, m = 0.2 kg
height of fall, h = 35 cm = 0.35 m
initial speed of the magnet, u = 0
final speed of the magnet, v = 1.5 m/s
Initial energy of the magnet is given by;
E₁ = P.E₁ + K.E₁
E₁ = mgh₁ + ¹/₂mu²
E₁ = (0.2 x 9.8 x 0.35) + ¹/₂(0.2)(0)²
E₁ = 0.686 J
Final energy of the magnet as it emerges from the tube is given by;
E₂ = mgh₂ + ¹/₂mv²
E₂ = (0.2 x 9.8 x 0) + ¹/₂(0.2)(1.5)²
E₂ = 0 + 0.225 J
The energy lost to the environment is given by;
E = E₂ - E₁
E = 0.225 J - 0.686 J
E = -0.461 J (negative sign indicates lost energy to the environment)
Therefore, the energy lost to the environment is 0.461 J