Answer:
The maximum height reached by the ball is 2.84 m
Step-by-step explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
![H = (U^2sin^2\theta)/(2g) \\\\H = ((13)^2(sin \ 35^0)^2)/(2*9.8)\\\\H = 2.84 \ m](https://img.qammunity.org/2021/formulas/physics/high-school/iobky7d26zbeapax89sc2upwaq9i3tkods.png)
Therefore, the maximum height reached by the ball is 2.84 m