Question

A landlord owns 3 condominiums, a 1-bedroom condo, a 2-bedroom condo, and a 3-

bedroom condo. The total rent she receives is $1240. She needs to make repairs on the

condos, and it costs 10% of the 1-bedroom condo's rent for its repairs, 20% of the 2-

bedroom for its repairs, and 30% of the 3-bedroom condo's rent for its repairs. The total

repair bill was $276. The 3-bedroom condo's rent is twice the 1-bedroom condo's rent.

How much is the rent for all three condos?

Answer 1

I bedroom condo = $280

2 bedroom condo = $400

3 bedroom condo = $560

Explanation:

Given that :

Total rental cost for all 3 condos = $1240

Let :

I bedroom condo = b

2 bedroom condo = c

3 bedroom condo = 2b

Hence,

b + c + 2b = 1240

3b + c = 1240 - - - (1)

REPAIR COST :

Total repair cost = $276

1 bedroom = 10% of b = 0.1b

2 bedroom = 20% of c = 0.2c

3 bedroom = 30% of 2b = 0.3 * 2b = 0.6b

Hence,

0.1b + 0.2c + 0.6b = 276

0.7b + 0.2c = 276 - - - (2)

From (2)

0.7b + 0.2c = 276

0.7b = 276 - 0.2c

b = (276 - 0.2c) / 0.7

Substitute b = (276 - 0.2c) / 0.7 into (1)

3(276/0.7 - 0.2c/0.7) + c = 1240

1182.8571 - 0.8571428c + c = 1240

1182.8571 + 0.1428571c = 1240

0.1428571c = 1240 - 1182.8571

0.1428571c = 57.1429

c = 57.1429 / 0.1428571

c = 400

3b + c = 1240

3b + 400 = 1240

3b = 1240 - 400

3b = 840

b = 840/3

b = 280

Hence,

I bedroom condo = $280

2 bedroom condo = $400

3 bedroom condo = 2(280) = $560