Answer:
C. c = 64
Explanation:
The question is incomplete. Here is the complete question.
What value of c makes the equation true? Assume x greater-than 0 and y greater-than 0
RootIndex 3 StartRoot StartFraction x cubed Over c y Superscript 4 Baseline EndFraction EndRoot = StartFraction x Over 4 y (RootIndex 3 StartRoot y EndRoot) EndFraction
c = 12
c = 16
c = 64
c = 81
Given the function;
![\sqrt[3]{(x^3)/(cy^4) } = \frac{x}{4y\sqrt[3]{y} }](https://img.qammunity.org/2021/formulas/mathematics/high-school/hec1b6kd4hofkmhn0wppy6f00gfezixf4w.png)
We are to find the value of c from the expression.
Step 1: Take the cube of both sides;
![(\sqrt[3]{(x^3)/(cy^4) } )^3= (\frac{x}{4y\sqrt[3]{y} })^3\\(x^3)/(cy^4) = \frac{x^3}{(4y)^3(\sqrt[3]{y} )^3}\\(x^3)/(cy^4) = (x^3)/((64y^3)(y))\\\\(x^3)/(cy^4) = (x^3)/(64y^4)\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/lj0qxjxg422fmc7xq0acdh1wo2agreohlt.png)
Step 2: compare the denominator of both sides of the equation;

Step 3: Divide both sides by y₄

Hence the value of c is 64. Option C is correct