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1. There are 10 people in a math club. Three people will be chosen for the Pi Day committee. How many different ways can club members structure the committee? a. 12 b. 120 c. 720 d. 604,800

1 Answer

3 votes

Answer: 120

Explanation:

From the question, we are informed that there are 10 people in a math club and that three people will be chosen for the Pi Day committee.

The number of different ways that the club members can structure the committee goes thus:

This can be solved by:

nCr = n! / r! (n - r)!

where n = 10

r = 3

= n! / r! (n - r)!

= 10! / 3! (10 - 3)!

= (10 × 9 × 8) / (3 × 2)

=120

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