Answer:
a. 1,000 trees
b. 3,250 trees
Explanation:
a. How many trees will they plant during the fifth year?
b. How many trees will they have planted by the end of the tenth year?
Using the sum of an arithmetic progression formula
Sn = n/2 {2a+(n-1)d}
Where,
Sn = Sum of an n terms
n = number of terms
a = first term
d = common difference
a.
n = 5
a = 100
d = 50
S5 = n/2 {2a+(n-1)d}
= 5/2 {2*100 + (5-1)50}
= 5/2 {200+(4)50}
= 5/2{200 + 200}
= 5/2(400)
= 2,000 / 2
= 1,000
S5 = 1,000 trees
b. Sn = n/2 {2a+(n-1)d}
n = 10
a = 100
d =50
S10 = 10/2{2*100 + (10-1)50}
= 5{200 + (9)50}
= 5{200 + 450}
= 5(650)
= 3,250
S10 = 3,250 trees