If an impulse of 400 Ns acts on an object for 15s, what is the force of the object?

Question

asked Apr 11, 2021 6.1k views

1 Answer

Mr Mixin · Answer 1 · 2021-04-17T20:33:03+0000

Answer:

J for impulse

t for time

F for force

formula is J=F×t

Step-by-step explanation:

putting values in eqs after rearranging

we need to find force so

F=J ÷t

F=400÷15

=26.67

=27(rounded off)

27N is the Force applied.