Question

The object was thrown vertically upwards at a speed of 30 m / s. How high does the body go?

and how long does it take to get back to the point of shooting?

Answer 1

4.9

Step-by-step explanation:

Velocity half second before maximum height = Velocity half second after maximum height (Return journey)

For downward journey :

Initial velocity u=0 m/s

We have g=9.8 m/s

Time t= ½s

s

Thus velocity after half second v=u+gt

v=0+9.8× ½ =4.9m/s