221k views
21 votes
F(1) =3 and f (n+1)= f(n)^2+3 then find the value of f(4)

User Mistic
by
4.5k points

1 Answer

10 votes

Answer:

f(4) = 1612

Explanation:

using the recursive formula and f(1) = 3 , then

f(2) = f(1)² + 3 = 3² + 3 = 9 + 3 = 12

f(3) = f(2)² + 3 = 144 + 3 = 147

f(4) = f(3)² + 3 = 147² + 3 = 1609 + 3 = 1612

User Thomas Makos
by
5.5k points