Question

A boat travels 28 m while it reduces its velocity from 27.5 m/s to 14.5m/s. What is the boat’s acceleration while it travels that distance?

Answer 1

9.75 m/s²

Step-by-step explanation:

Given that,

v= 14.5 m/s

u = 27.5 m/s

s = 28 m

a = ?

v² = u² -2as [ minus sign due to deceleration]

14.5² = 27.5² - 2 × a × 28

210.25 - 756.25 = -56a

-56a = -546

a = 9.75 m/s²