Question

a sample of carbon dioxide gas occupies a volume of 20 L at standard temperature and pressure (STP). what will be the volume of a sample of argon gas that has the same number of moles and but tripled the absolute temperature?​

Answer 1

Volume of Argon = 59.972 L

Further explanation

In general, the gas equation can be written

`\large {\boxed {\bold {PV = nRT}}}`

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

At STP(0 C, 1 atm), 1 mol gas= 22.4 L

so for 20 L

`\tt (20)/(22.4)=0.893`

For Argon

P = 1 atm

T = 273 K x 3 =819 K (tripled)

n = 0.893 (the same number of moles)

R = 0.082 L/atm.mol K

`\tt V=(nRT)/(P)=(0.893* 0.082* 819)/(1)=59.972~L`