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What is the density of 9 cm³ gold cube with 450 g in a mass?​

User Barrowc
by
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1 Answer

0 votes

Answer:

Answer is 50g/cm^3

Explanation:

soln,

Volume of the gold cube = 9 cm^3

Mass of the gold cube = 450 g

now,

density= mass/volume

=450 / 9

=50 g/cm^3

{Therefore, the density of the gold cube is 50 g/cm^3.}

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