Question

What is the pH of a solution that contains 0.0003 moles of KOH in 410 mL of solution?

Answer 1

Answer: 10.865

Step-by-step explanation:

The molarity of the solution is
`(0.0003)/(0.410)=0.0007317073 \text{ M}`.

So, the pOH is
`-\log(0.0007317073)=3.135`

Since pH + pOH = 14, the pH is 14-3.135, which is about 10.865