Question

There is friction between the block and the

table.
The suspended 2 kg mass on the left is
moving up, the 4 kg mass slides to the right
on the table, and the suspended mass 4 kg on
the right is moving down.
The acceleration of gravity is 9.8 m/s
2
.What is the magnitude of the acceleration
of the system?
1. 1.67253
2. 1.9845
3. 1.75311
4. 2.47673
5. 2.1315
6. 2.058
7. 2.548
8. 1.33933
9. 1.5288
10. 2.03127
Answer in units of m/s
2
.

Answer 1

The acceleration of the system is 2.03127 m/s².

Step-by-step explanation:

The acceleration of the system can be calculated by considering the forces acting on the two masses. First, we need to find the net force on each mass:

For the 2kg mass moving up, the net force is the tension in the string minus the weight:

F_net = T - m_2 * g = T - (2kg) * (9.8 m/s^2)

For the 4kg mass sliding to the right, the net force is the force of friction:

F_net = f_f = m_1 * g * Mu = (4kg) * (9.8 m/s^2) * 0.40

To find the acceleration, we equate the net force on each mass to its mass times acceleration:

T - (2kg) * (9.8 m/s^2) = (2kg) * a

(4kg) * (9.8 m/s^2) * 0.40 = (4kg) * a

Solving these equations gives us:

a = 2.03127 m/s^2

Answer 2

5 no

Step-by-step explanation:

actually the 4kg lying on table has no influence

it slides towards 4kg weight hung

as it has excess 2kg force

force=miu × m ×g