Answer:
(B
The given system of equations are:
y=x^2+3x+3y=x
2
+3x+3 (1)
and y=x^2+x+2y=x
2
+x+2 (2)
Subtracting equation (2) from (1), we get
0=2x+10=2x+1
⇒2x=-12x=−1
⇒x={\frac{-1}{2}}x=
2
−1
⇒x=-0.5x=−0.5
Now, substituting the value of x=-0.5 in equation (2), we get
y=0.25-0.5+2y=0.25−0.5+2
⇒y=1.7y=1.7
Thus, the values of x and y are -0.5 and 1.7.
Therefore, the approximate solution of the given system of the equation is (-0.5, 1.7).
Hence, option (B) is correct.