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What is the length of segment DF?

B
4/28
1
68°
C
2
А A
2
3
8
4
68°
28°
F
5
Type your answer.

What is the length of segment DF? B 4/28 1 68° C 2 А A 2 3 8 4 68° 28° F 5 Type your-example-1
User Laverick
by
5.4k points

1 Answer

4 votes

Answer:

DF = 17.12

Explanation:

From the picture attached,

From ΔABC and ΔEFD,

m∠ABC = m∠EFD = 28°

m∠BAC = m∠EDF = 68°

By AA property of similarity, ΔABC and ΔEFD will be similar.

And their corresponding sides will be proportional.


(AB)/(EF)=(BC)/(DF)=(AC)/(ED)


(4)/(EF)=(BC)/(DF)=(2)/(8)


(4)/(EF)=(1)/(4)

EF = 16

Now by applying cosine rule in ΔDEF,

DF² = ED² + EF² - 2(ED)(EF)cos(E)

DF² = 8² + (16)² - 2(8)(16)cos(84)°

DF² = 320 - 26.76

DF = √(293.24)

DF = 17.12

User Zekus
by
5.6k points