Question

Quadratic formula

`{4v}^(2) - 16v + 7 = 0`
Please help​

Answer 1

`~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{4}v^2\stackrel{\stackrel{b}{\downarrow }}{-16}v\stackrel{\stackrel{c}{\downarrow }}{+7}=0 \qquad \qquad v= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ v= \cfrac{ - (-16) \pm \sqrt { (-16)^2 -4(4)(7)}}{2(4)} \implies v= \cfrac{ 16 \pm \sqrt { 256 -112}}{ 8 } \\\\\\ v=\cfrac{16\pm√(144)}{8}\implies v=\cfrac{16\pm 12}{8}\implies v= \begin{cases} (7)/(2)\\[1em] (1)/(2) \end{cases}`