Question

Three numbers have the sum of 112. The first number is twice the second and the third number us twice the first. What is the smallest of the 3 numbers?

Answer 1

x = 16

Explanation:

Let the second number be x.

The first number = 2x

The third number = 2×2x = 4x

2x + x + 4x = 112

7x = 112

x = 112/7

x = 16