Question

How do I solve this equation?
(-4x+12)^1/2 = x

Answer 1

`(-4x+12)^(1/2)=x\\√(-4x+12)=x\\\\D:-4x+12\geq0\wedge x\geq0\\D:4x\leq12\wedge x\geq0\\D:x\leq3\wedge x\geq0\\D:x\in\langle0,3\rangle\\\\√(-4x+12)=x\\-4x+12=x^2\\x^2+4x-12=0\\x^2-2x+6x-12=0\\x(x-2)+6(x-2)=0\\(x+6)(x-2)=0\\x=-6 \vee x=2\\\\-6\\ot \in D\\\\\boxed{x=2}`