Question

Pls help me with this problem :)

The areas of two similar triangles are 9 cm² and 49 cm². One of the sides of the first
triangle is 2 cm. What is the length of the corresponding side of the other triangle?

Answer 1

I believe it should be rounded to 11, if not decimal would be 10.88

Explanation:

49 divided by 9 equals 5.44 which is the amount times the 49cm^2 triangle is compared to the 9cm^2. So then the side is 2cm, multiply by the amount times bigger the other triangle is which would be 10.88. Hopefully I'm not wrong:)

Answer 2

The answer is 4 and 2/3 cm²

Explanation:

Take the square root of 49 and 9 and you'll get 7 and 3 since the scale factor is the large area over the small area.

The large area would be √49 cm²

The small area would be √9 cm²

7 x cm

------ = ----------, cross multiply

3 2 cm

7 × 2 = 3 × x

14 = 3x

x = 14/3, x = 4 and 2/3