93.8k views
1 vote
An object is projected straight upward with an initial speed of 25.0 m/s. What's the maximum height obtained by the object ?

User Rub
by
5.3k points

1 Answer

3 votes

Answer:

The maximum height obtained by the object is approximately 31.855 m

Step-by-step explanation:

The vertical velocity of the object = 25.0 m/s

The height reached by the object, is given by the following formula;

v² = u² - 2 × g × h

Where;

u = The initial velocity of the object = 25.0 m/s

v = The final speed of the object = 0 m/s at maximum height

h = The maximum height obtained by the object

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values, gives;

0² = (25.0 m/s)² - 2 × 9.81 m/s² × h

2 × 9.81 m/s² × h = (25.0 m/s)²

h = (25.0 m/s)²/(2 × 9.81 m/s²) ≈ 31.855 m

The maximum height obtained by the object, h ≈ 31.855 m.

User Sederqvist
by
4.7k points