125k views
5 votes
Find an equation for the line below in y=mx+b

Find an equation for the line below in y=mx+b-example-1
User Autonocat
by
8.6k points

1 Answer

3 votes

Answer:

y = -1/2x - 11/2

Explanation:

Using slope intercept form y = mx + b, to determine the equation, first count the rise(vertical or change in y), and run(horizontal or change in x) of the line.

m is the slope, b is the y-intercept which will remain when x is 0 as this will cancel out the m.

Be careful when determining the slope, and pay attention to the steps(count) of the x, and y axis.

As this graph measures a line with a negative slope passing through the y axis at -5 1/2 → -11/2, with a step of 1, we can count the squares normally to determine the slope.

So since we know that this line has two obvious points (-5,-3) and (1,-6) we can use the equation for slope to measure it's steepness.

m = y2-y1/x2-x1

with (x1,y1) being the first point, and (x2,y2) being the second point.

So: (negative minus a negative makes a positive)

m = -6-(-3)/1-(-5) = -6 + 3/ 1 + 5 = -3/6 = -1/2.

Since m = -1/2, and b = -11/2, the line must be y = -1/2x - 11/2.

User Lojza
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories