29.9k views
2 votes
Solve the following compound inequality.

5x + 7 ≤ -3 OR 3x - 4 ≥ 11

A. -2 ≤ x ≤ 5

B. x ≤ -2 OR x ≥ 5

C. x ≤ -15 OR x ≥ 12

D. x ≥ 5

Thank you!

1 Answer

3 votes

Answer:

B

Explanation:

We have the compound inequality:


5x+7\leq-3 \text{ or } 3x-4\geq 11

Since this is an “OR” inequality, we can solve each inequality individually. So:

1)

We have:


5x+7\leq-3

Subtract 7 from both sides:


5x\leq -10

Divide both sides by 5:


x\leq-2

So, the first solution is above.

2)

We have:


3x-4\geq 11

Add 4 to both sides:


3x\geq15

Divide both side by 3:


x\geq5

Our second solution is above.

Therefore, our solution is:


x\leq -2 \text{ or } x\geq5

Since our original inequality is “OR,” our solution set remains an “OR.”

Hence, our answer is B.

User Csterling
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories