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The costume jewelry and accessories for the show are bought from sales racks at two different stores on different days. Use x to represent the price of each item on the sales rack at the first store and y to represent the price of each item on the sales rack at the second store.

On the first day, the students spent $30 on 4 items from the first store and 7 items from the second store. On the second day, the students spent $22 on 3 items from the first store and 5 items from the second store. On the third day, the students need to buy 10 items from the first store and 17 items from the second store.

What is the amount of money the students will need on the third day? Find your answer by creating and solving a system of linear equations based on the first day and the second day. Explain your reasoning.

User Abhiburk
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1 Answer

5 votes

Answer:

74

Explanation:

Using linear equations, we are given two equations from the questions:

4x +7y=30 from day one and 3x +5y=22 from day two

Multiply the first equation by 3 and second by 4 giving us

12x +21y=90 and 12x +20y=88. Minus both equations.

12x - 12x +21y - 20y= 90 - 88, Gives you y=2,

You can now use the value of y to find x.

4x + 7y = 30

4x + 7(2)= 30

4x + 14= 30. Minus 14 on both sides giving you

4x=16. Divide both sides by 4.

x=4

Now use both values to find how much money is needed on the third day.

10x + 17y

=10(4) + 17(2)

=40 +34

=74

User Tilman Vogel
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