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Solve Sec(2x)-4=0 for the first two positive solutions. thanks!

1 Answer

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sec(2x) - 4 = 0

sec(2x) = 4

1 / cos(2x) = 4

cos(2x) = 1/4

2x = cos⁻¹(1/4) + 2 or 2x = -cos⁻¹(1/4) + 2

(where n is any integer)

x = 1/2 cos⁻¹(1/4) + or x = -1/2 cos⁻¹(1/4) +

The first two positive solutions occur for n = 0 in the first family of solutions, and for n = 1 in the second family, so

x = 1/2 cos⁻¹(1/4) or x = π - 1/2 cos⁻¹(1/4)

x ≈ 0.659 or x ≈ 2.483

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