Question

Given: AABC, mZACB=90°,
CD I AB ,mZACD=60°,
BC = 6 cm
Find: CD, Area of AABC

Answer 1

Check the picture below.

so, since we know the height of the triangle and its base is simply a + b, then

`\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=\stackrel{a}{9}+\stackrel{b}{3}\\ \qquad 12\\ h=3√(3) \end{cases}\implies A=\cfrac{1}{2}(12)(3√(3))\implies A=18√(3)`