Question

Pls Help I’m so confused how do you do this

Answer 1

Answer: A

Explanation:

`$$Given $m \angle A=9 x-7, \quad m \angle B=7 x-9, m \angle C=28-2 x$ \\For the triangle $m \angle A+m \angle B+m \angle c=180$$$\begin{aligned}&\Rightarrow(9 x-7)+(7 x-9)+(28-2 x)=180 \\&\Rightarrow 9 x+7 x-2 x-7-9+28=180 \\&\Rightarrow 14 x=180-28+16 \\&\Rightarrow 14 x=168 \\&\Rightarrow \quad x=12\end{aligned}`

`$$Therefore,\\&m \angle A=9 x-7=9 * 12-7=101^(\circ)\\&m \angle B=7 x-9=7 * 12-9=75^(\circ) \\&m \angle C=28-2 x=28-2 * 12=28-24=4^(\circ)\\`

`$$Since $m \angle A=101^(\circ)$ so $B C$ is the longest side of a triangle $\triangle A B C$ \\\\Since $m \angle C=4^(\circ) S 0$ SB is the shortest side of a triangle $\triangle A B C$\\\\So listing the sides in $\triangle A B C$ from shortest to longest is: (a) $\overline{A B}, \overline{A C}, \overline{B C}$`