Question

Solve the following equations for 0 ≤ theta ≤ 360º cosec(2 — 45°) = 2​

Answer 1

Explanation:

here ,

`cosec \alpha = (1)/( \sin( \alpha ) )`

now,

cosec(2-45°)=2

or,

1/sin(2-45°) =2

or,

1/sin2cos45°-cos2sin45=2

or,

`(1)/( \sin(2) (1)/(2) - \cos(2) (1)/(2) ) = 2`

or,

sorry I have that much qualifications to work on this question and hoping this much will make bit easy for you to solve it further