71.7k views
16 votes
Find the equation of a line that is parallel to y=3x+6 and passes through A

) (0,-2) B. (2,5) C.(4,1)

User Anoel
by
8.2k points

1 Answer

4 votes

Answer:

Explanation:

We'll look for an equation with the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0.

A line parallel to y=3x+6 will have the same slope, 3.

We can write y=3x+b. Any value of b can be used to generate a parallel line.

If we want that line to go through a specific point, such as (0,-2), we need to find a value of b that shifts the line so that it includes (0,-2). This can be done by using that point in the equation y=3x+b:

y=3x+b

-2=3*(0)+b for point (0,-2)

b = -2

The equation becomes y=3x-2

See the attached plot.

===========================

Do that same thing for the remaining two points.

For B: (2,5) The equation is y=3x-1

For C: (4,1) The equation is y=3x-11

Find the equation of a line that is parallel to y=3x+6 and passes through A ) (0,-2) B-example-1
User Andreas Hindborg
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories