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Find the equation of a line that is parallel to y=3x+6 and passes through A

) (0,-2) B. (2,5) C.(4,1)

User Anoel
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1 Answer

4 votes

Answer:

Explanation:

We'll look for an equation with the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0.

A line parallel to y=3x+6 will have the same slope, 3.

We can write y=3x+b. Any value of b can be used to generate a parallel line.

If we want that line to go through a specific point, such as (0,-2), we need to find a value of b that shifts the line so that it includes (0,-2). This can be done by using that point in the equation y=3x+b:

y=3x+b

-2=3*(0)+b for point (0,-2)

b = -2

The equation becomes y=3x-2

See the attached plot.

===========================

Do that same thing for the remaining two points.

For B: (2,5) The equation is y=3x-1

For C: (4,1) The equation is y=3x-11

Find the equation of a line that is parallel to y=3x+6 and passes through A ) (0,-2) B-example-1
User Andreas Hindborg
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