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Given: AABC, mZACB=90°, CD I AB ,mZACD=60°, BC = 6 cm Find: CD, Area of AABC
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Given: AABC, mZACB=90°,
CD I AB ,mZACD=60°,
BC = 6 cm
Find: CD, Area of AABC

Given: AABC, mZACB=90°, CD I AB ,mZACD=60°, BC = 6 cm Find: CD, Area of AABC-example-1
User Omegacore
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1 Answer

1 vote

Check the picture below.

so, since we know the height of the triangle and its base is simply a + b, then


\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=\stackrel{a}{9}+\stackrel{b}{3}\\ \qquad 12\\ h=3√(3) \end{cases}\implies A=\cfrac{1}{2}(12)(3√(3))\implies A=18√(3)

Given: AABC, mZACB=90°, CD I AB ,mZACD=60°, BC = 6 cm Find: CD, Area of AABC-example-1
User ColacX
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3.0k points
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