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How many molecules are present in 4.21 moles of HBr?​

1 Answer

3 votes

Answer:

The answer is

2.53 × 10²⁴ molecules

Step-by-step explanation:

The number of molecules present can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.21 × 6.02 × 10²³

We have the final answer as

2.53 × 10²⁴ molecules

Hope this helps you

User HII
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