Answer:
![\displaystyle y-1=(1)/(3)(x+3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9zz5g9d5tqil63mtx09dkgu4rmw7560yrt.png)
Explanation:
Equation of a Line
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:
![\displaystyle y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)](https://img.qammunity.org/2021/formulas/mathematics/college/23qadvao41i7o4ifvkjzluiximg3ahexep.png)
The table shows the relation between x and y. It contains the following points
(-3,1), (6,4), (12,6), (30,12).
Taking the two first points, we find the equation of the line:
![\displaystyle y-1=(4-1)/(6+3)(x+3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4rlct4pe91eotgecdhhocqiuspfumtxonu.png)
![\displaystyle y-1=(3)/(9)(x+3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/macbi8pjckci5yo4xd62qgfkleew344v55.png)
Simplifying:
![\displaystyle y-1=(1)/(3)(x+3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9zz5g9d5tqil63mtx09dkgu4rmw7560yrt.png)
To ensure the rest of the points belong to the line, we test them:
For the point (12,6):
![\displaystyle 6-1=(1)/(3)(12+3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/b4grxer9zgn5fn8squgmhprcztnt0i8smg.png)
![\displaystyle 5=(1)/(3)(15)](https://img.qammunity.org/2021/formulas/mathematics/high-school/zl5swtlhp7kf6kwb4rk506u7lobvlkp4a7.png)
5=5
Since equality is true, the point belongs to the line.
For the point (30,12):
![\displaystyle 12-1=(1)/(3)(30+3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/6y68fgan2bd13x1pvub3676cntytnyk7o7.png)
![\displaystyle 11=(1)/(3)(33)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5ywv1s1ahkdqh4fcva5alqm52h6rlnjhqj.png)
11=11
Since equality is true, the point belongs to the line.
Thus, the equation of the line is:
![\mathbf{\displaystyle y-1=(1)/(3)(x+3)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/kpeldft9jq9rkn552f7g0n02g7iv1hwiz9.png)