Answer:
16%
Explanation:
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score = 12.5 minutes
μ is the population mean = 17 minutes
σ is the population standard deviation = 4.5 minutes
z = 12.5 - 17/4.5
z = -1
Probability value from Z-Table:
P(x<12.5) = 0.15866
Converting to percentage
= 0.15866 × 100
= 15.866%
Approximately , the percentage of people living in Flint have a travel time to work that is less than 12.5 minutes is 16%