Question

A block with a mass M = 4.85 kg is resting on a slide that has a curved surface. There is no friction. The speed of the block after it has slid along the slide sufficiently far for its vertical drop to be 19.6 m is:__________a. 19.6 m/s b. 384 m/s c. 93 m/s d. 43.2 m/s e. The problem cannot be solved because the shape of the curved slide is not given.

Answer 1

The correct option is a

Step-by-step explanation:

From the question we are told that

The mass of the block is
`m = 4.84 \ kg`

The height of the vertical drop is
`h = 19.6 \ m`

Generally from the law of energy conservation , the potential energy at the top of the slide is equal to the kinetic energy at the point after sliding this can be mathematically represented as

`PE = KE`

i.e
`m * g * h = (1)/(2) * m * v^2`

=>
`gh = 0.5 v^2`

=>
`v = \sqrt{(9.8 * 19.6)/(0.5 ) }`

=>
`v = 19.6 \ m/s`