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Colton bounces a ball 3.268 feet infront of his feet. The path of the ball from the time it hits the ground until it lands on the floor is represented by

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here is the complete and correct question. Colton bounces a ball 3.268 feet in front of his feet. The path of

the ball from the time it hits the ground until it lands on the floor is represented by

f(x) =-4(x - 5)2 + 12

Assuming that Colton's feet are located at the origin, (0, 0), what is the maximum height of the ball (in feet)?

Answer:

12ft

step by step explanation:

This equation has been written in vertex form, and it has its vertex at (5, 12). Because the scale factor is not positive, it has a negative value, the graph for the question is going to open downward, such that the vertex,

that is the maximum height is 12 ft.

we have The equation of a parabola with vertex (h, k) to be

f(x) = a(x -h)² + k

when put in Comparison to your question function, we get that

a=-4

h=5

k=12

so the vertex (h, k) = (5, 12).

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