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6/(x^2-3x)=12/x+1/(x-3)
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6/(x^2-3x)=12/x+1/(x-3)

User ToddBFisher
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\\ \rm\Rrightarrow (6)/(x^2-3x)=(12)/(x)+(1)/(x-3)


\\ \rm\Rrightarrow (6)/(x(x-3))=(12)/(x)+(1)/(x-3)


\\ \rm\Rrightarrow (6)/(x(x-3))=(12(x-3)+x)/(x(x-3))


\\ \rm\Rrightarrow 6=12x-36+x


\\ \rm\Rrightarrow 6=13x-36


\\ \rm\Rrightarrow 13x=42


\\ \rm\Rrightarrow x=(42)/(13)

User BrandonLWhite
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