Given:
After 8 months, you have been able to save $937.
You have the ability to save $130 per month.
To find:
The model for the situation and y-intercept and rate of change.
Solution:
Let y be the ability to saving after x months.
Ability to save in one month = $130
Ability to save in x months = $130x
So, total ability is
...(i)
where, b is initial savings.
After 8 months, you have been able to save $937. So, the point is (8,937).
Put x=8 and y=937 in (i),
![937=130(8)+b](https://img.qammunity.org/2021/formulas/mathematics/high-school/c0ygalgvsvh3lh4lu7sd8z49y7xb83ahr6.png)
![937=1040+b](https://img.qammunity.org/2021/formulas/mathematics/high-school/ryx3o2b1ezuyon1s65dtk8uqbdzoqoqcbx.png)
![937-1040=b](https://img.qammunity.org/2021/formulas/mathematics/high-school/4ocoq6i3ajqwfefrc97lfbq4j9efsjoiws.png)
![-103=b](https://img.qammunity.org/2021/formulas/mathematics/high-school/fll321ip9fl5st1avxxu79yq19rti4esbn.png)
So, the y-intercept is -103. Here, negative sign represents that we cannot able to save initially or we have loan or liabilities of $103.
Put b=-103 in (i).
![y=130x-103](https://img.qammunity.org/2021/formulas/mathematics/high-school/ifvx9i97c4r06j0jp7zuf97hkj3d1y4aho.png)
On comparing with slope intercept form, we get
Slope = 130 and y-intercept = -103
Therefore, the slope is 130 and y-intercept is -103.