Question

An ideal gas had a mass of 0.0218g and occupied a volume of 1.111L at 0oC and 0.0100atm. What is the molar mass of this gas?

Answer 1

Step-by-step explanation:

we shall use gas law formula to solve the problem .

P = .01 atm

V = 1.111 L

T = 273 K

mass of gas = .0218

molar mass = M

no of moles n = .0218 / M

PV = n RT

.01 x 1.111 = (.0218 / M) x .082 x 273

.0218 / M = .000496

M = .0218 / .000496

= 43.95