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What is the concentration of chloride ions in a solution that contains 0.375 g of aluminum chloride in 15.0 mL of solution?

User Will Green
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1 Answer

5 votes

Answer:

0.561 M

Step-by-step explanation:

Step 1: Given data

  • Mass of aluminum chloride (m): 0.375 g
  • Molar mass of aluminum chloride (M): 133.34 g/mol
  • Volume of the solution (V): 15.0 mL

Step 2: Calculate the molar concentration of aluminum chloride (C)

We will use the following expression.


C = (m)/(M * V(L) ) = (0.375g)/(133.34 g/mol * 0.0150L ) = 0.187M

Step 3: Write the reaction of dissociation of aluminum chloride

AlCl₃(aq) ⇒ Al³⁺(aq) + 3 Cl⁻(aq)

Step 4: Calculate the concentration of chloride ions

The molar ratio of AlCl₃ to Cl⁻ is 1:3. The concentration of Cl⁻ is 3/1 × 0.187 M = 0.561 M

User Edy Ionescu
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