Question

What mass of a solution labeled 6.3% sucrose (C12H22O11, 342 g/mol) by mass contains 11.0 g of sucrose?

Answer 1

To determine the mass of a 6.3% sucrose solution containing 11.0 g of sucrose, use the percentage to set up a ratio and solve for the total mass. The calculated mass is 174.6 grams.

Step-by-step explanation:

The student is asking about the mass of a 6.3% sucrose solution that contains 11.0 g of sucrose. To find the total mass of the solution, we can use the percentage concentration of sucrose in the solution. Since 6.3% of the solution's mass is sucrose, we can set up a proportion where 6.3% (or 0.063) is equal to 11.0 g divided by the total mass of the solution (let's call this 'x'). The equation to solve is 0.063 = 11.0 g / x. By solving for 'x', we find that x = 11.0 g / 0.063, which is approximately 174.6 g. Therefore, 174.6 grams of the sucrose solution contains 11.0 g of sucrose.

Answer 2

174.6g of solution contains the 11.0g of sucrose

Step-by-step explanation:

A solution of 6.3% by mass of sucrose contains 6.3g of sucrose in 100g of solution, that is, 6.3g of sucrose / 100g of solution.

As we want to find the mass contains 11.0g of sucrose, we can write:

11.0g of sucrose * (100g of solution / 6.3g of solution) =

174.6g of solution contains the 11.0g of sucrose