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The probability of event A is 0.2 and probability of event B is 0.3. Given that A and B are independent, then the probability of A and B (A intersection B) is: Choose one • 10 points 5% 6% 9% 13%

1 Answer

5 votes

Answer:


P(A\ n\ B) = 6\%

Explanation:

Given


P(A) = 0.2


P(B) = 0.3

Required

Determine
P(A\ n\ B)

Since both events are independent;


P(A\ n\ B) = P(A) * P(B)


P(A\ n\ B) = 0.2 * 0.3


P(A\ n\ B) = 0.06

Convert to %


P(A\ n\ B) = 0.06 * 100\%


P(A\ n\ B) = 6\%

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