Question

A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.3 m/s. The drag force is of the form bv2 What is the value of b?

Answer 1

The value is
`b = 0.00026 \ kg / m`

Step-by-step explanation:

From the question we are told that

The mass of the Ping-Pong is
`m = 2.3 \ g = 0.0023 \ kg`

The terminal speed is
`v = 9.3 \ m/s`

The drag force is
`bv^2`

Generally the resultant force on the Ping- Pong is mathematically represented as

`F = mg - bv^2`

when terminal velocity is attained , the resultant force is zero so

`0 = mg - bv^2`

=>
`b = (m * g)/(v^2)`

=>
`b = (0.0023 * 9.8)/( 9.3 ^2)`

=>
`b = 0.00026 \ kg / m`